X^2+13x=33

Solution for X^2+13x=33 equation:

X^2+13X=33

We move all terms to the left:

X^2+13X-(33)=0

a = 1; b = 13; c = -33;
Δ = b2-4ac
Δ = 132-4·1·(-33)
Δ = 301
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{301}}{2*1}=\frac{-13-\sqrt{301}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{301}}{2*1}=\frac{-13+\sqrt{301}}{2}
$